What is thermal conductivity (lambda value)?

Thermal conductivity, written as the Greek letter lambda (λ) and sometimes called the k-value, indicates how much heat a material conducts. The unit is W/(m·K): the number of watts flowing through a layer 1 m thick and 1 m² in area for a 1 degree temperature difference. The lower the lambda value, the better the material insulates.

Typical values

Material λ in W/(m·K)
PIR insulation approx. 0.022 to 0.026
EPS approx. 0.030 to 0.038
Mineral wool approx. 0.032 to 0.040
Softwood approx. 0.13
Brickwork approx. 0.5 to 0.9
Reinforced concrete approx. 2 to 2.5
Steel approx. 50
Aluminium approx. 160 to 200

Always use the manufacturer’s declared value.

From lambda to R-value

The thermal resistance of a layer is R = thickness (m) / λ.

Example: 100 mm EPS with λ = 0.035 gives R ≈ 2.9 m²K/W. With PIR (λ = 0.023) about 67 mm achieves the same R. A lower lambda therefore means a thinner build-up for the same performance, useful where space is tight.

Insulation thickness for the same R-valueEPS (λ = 0.035)EPS (λ = 0.035): 100 mm100 mmPIR (λ = 0.023)PIR (λ = 0.023): 67 mm67 mm
Thickness needed to reach R ≈ 2.9 m²K/W, using the article's example values: EPS with λ = 0.035 and PIR with λ = 0.023 W/(m·K). The PIR thickness is approximate. Always use the manufacturer's declared value.

Tips for comparing insulation

  1. Use the declared value (λD) from the product’s declaration of performance.
  2. Compare cost per unit of R-value, not per centimetre.
  3. Workmanship counts: gaps and thermal bridges undo a good lambda on paper.
  4. Moisture: wet insulation conducts heat much better than dry. Keep it dry on site.

Related terms

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